x^2+33x+140=0

Solution for x^2+33x+140=0 equation:

x^2+33x+140=0

a = 1; b = 33; c = +140;
Δ = b2-4ac
Δ = 332-4·1·140
Δ = 529
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{529}=23$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(33)-23}{2*1}=\frac{-56}{2}
=-28
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(33)+23}{2*1}=\frac{-10}{2}
=-5
$